We can think of

We will work with the **Dirac equation** and its transformation.
We know how the Lorentz vectors transform so we can derive a requirement on the spinor transformation.
(Remember that
works in an entirely different space than do
and
.)

The transformed equation will be the same as the Dirac equation if . Multiply by the inverse Lorentz transformation.

Rotations and boosts are symmetry transformations of the coordinates in 4 dimensions. Consider the cases of rotations about the z axis and boosts along the x direction, as examples.

The

We verify that a boost along the direction is like a rotation in the plane through an angle .

We need to **find the transformation matrices**
that satisfy the equation
for the Dirac equation to be covariant.
Recalling that the 4 component equivalent of
is
,
we will show that these matrices are (for a rotation in the xy plane and a boost in the x direction).

Note that this is essentially the transformation that we derived for rotations of spin one-half states extended to 4 components. For the case of the boost the angle is now .

Lets **verify that this choice works for a boost**.

The equation we must satisfy can be checked for each matrix. First check . The operations with the matrices all come from the anticommutator, , which tells us that the square of any gamma matrix is one and that commuting a pair of (unequal) matrices changes the sign.

That checks for . Now, try .

That one also checks. As a last test, try .

The Dirac equation is therefore shown to be

The pure rotation about the z axis should also be verified.

For or 4, and the requirement is fairly obviously satisfied. Checking the requirement for , we get.

This also proves to be the right transformation of so that the

Despite the fact that we are using a vector of constant matrices, , the Dirac equation is covariant if we choose the right transformation of the spinors. This allows us to move from one coordinate system to another.

As an example, we might try our solution for a free electron with spin up along the z axis at rest.

The solution we found for a free particle with momentum was.

Imagine we boost the coordinate system along the direction with . We can transform the momentum of the electron to the new frame.

The momentum along the x direction is . We now have two ways to get the free particle state with momentum in the x direction. We can use our free particle state

where the normalization factor is now set to be , defining this as the primed system.

We can also find the same state by boosting the at rest solution. Recall that we are boosting in the x direction with , implying .

In the last step the simple Lorentz contraction was used to set . This

Jim Branson 2013-04-22