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Derive Spin \bgroup\color{black}${1\over 2}$\egroup Rotation Matrices

In section 1.10.3, we derived the expression for the rotation operator for orbital angular momentum vectors. The rotation operators for internal angular momentum will follow the same formula.

\begin{eqnarray*}
& R_z(\theta)=e^{i\theta S_z\over\hbar}=e^{i{\theta\over 2}\si...
...{n=0}^\infty {\left({i\theta\over 2}\right)^n\over n!}\sigma_j^n
\end{eqnarray*}



We now can compute the series by looking at the behavior of \bgroup\color{black}$\sigma_j^n$\egroup.

\begin{eqnarray*}
&\sigma_z=\pmatrix{1 & 0\cr 0 & -1} & \sigma_z^2=\pmatrix{1 & ...
...matrix{0 & 1\cr 1 & 0} & \sigma_x^2=\pmatrix{1 & 0\cr 0 & 1} \\
\end{eqnarray*}



Doing the sums

\begin{eqnarray*}
& R_z(\theta)=e^{i{\theta\over 2}\sigma_z}=
\pmatrix{\sum\limi...
...{\theta\over 2} \cr i\sin{\theta\over 2} & \cos{\theta\over 2} }
\end{eqnarray*}



Note that all of these rotation matrices become the identity matrix for rotations through 720 degrees and are minus the identity for rotations through 360 degrees.



James Branson
2001-09-17