The expectation value of \bgroup\color{black}${p^2\over 2m}$\egroup in eigenstate

The expectation value of \bgroup\color{black}${p^2\over 2m}$\egroup is

\begin{eqnarray*}
\langle u_n\vert{p^2\over 2m}\vert u_n\rangle
&=&{-1\over 2m}...
...n\rangle \\
&=&{\hbar\omega\over 4}((n+1)+n)={1\over 2}E_n \\
\end{eqnarray*}


(See the previous section for a more detailed computation of the same kind.)



Jim Branson 2013-04-22