The expectation value of \bgroup\color{black}$p$\egroup in eigenstate

(See the previous example is you want to see all the steps.) The expectation value of \bgroup\color{black}$p$\egroup also gives zero.

\begin{displaymath}\bgroup\color{black} \langle u_n\vert p\vert u_n\rangle=-i\sq...
...a\over 2}\langle u_n\vert A-A^\dagger\vert u_n\rangle=0 \egroup\end{displaymath}



Jim Branson 2013-04-22